732=2x^2+10x+48

Solution for 732=2x^2+10x+48 equation:

732=2x^2+10x+48

We move all terms to the left:

732-(2x^2+10x+48)=0

We get rid of parentheses

-2x^2-10x-48+732=0

We add all the numbers together, and all the variables

-2x^2-10x+684=0

a = -2; b = -10; c = +684;
Δ = b2-4ac
Δ = -102-4·(-2)·684
Δ = 5572
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5572}=\sqrt{4*1393}=\sqrt{4}*\sqrt{1393}=2\sqrt{1393}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{1393}}{2*-2}=\frac{10-2\sqrt{1393}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{1393}}{2*-2}=\frac{10+2\sqrt{1393}}{-4}
$